x^2-8=2x^2

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Solution for x^2-8=2x^2 equation: 



x^2-8=2x^2

We move all terms to the left:

x^2-8-(2x^2)=0

We add all the numbers together, and all the variables

-1x^2-8=0

a = -1; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·(-1)·(-8)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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